PHP Issue: Function parameter is not retaining the full string

Cause:
If your string contains a $, PHP interprets it as the start of a variable. For example:

<?php
display("$vhkvdov#jqlydk#p*_L#1qrlws|ufqh#KWLZ#1hwdgsX");
?>

Here, PHP will try to replace $vhkvdov with the value of a variable named $vhkvdov. Since that variable likely doesn’t exist, it evaluates to nothing, breaking the string.

Solution:
Use single quotes to prevent variable interpolation:

<?php
display('$vhkvdov#jqlydk#p*_L#1qrlws|ufqh#KWLZ#1hwdgsX');
?>

Additional Tip:

Enable error reporting during development to catch such issues early. In your php.ini, set:

error_reporting = E_ALL | E_NOTICE
display_errors  = On

; or alternatively
log_errors = On
error_log  = PATH/TO/YOUR/LOG.file   ; ensure this file is writable by the web server

With this, PHP will show helpful messages such as:

PHP Notice: Undefined variable: vhkvdov